tag:blogger.com,1999:blog-4087678678967641447.post3789076279621366849..comments2024-06-16T14:32:37.606+05:30Comments on Forward Junction Puzzles: Solve Banana Clock Hexagon Puzzle - with AnswerForward Junctionhttp://www.blogger.com/profile/09656543763051221546noreply@blogger.comBlogger7125tag:blogger.com,1999:blog-4087678678967641447.post-45997152051462833072018-07-26T15:34:13.005+05:302018-07-26T15:34:13.005+05:30Kim, I think the shapes add up to 15 because the n...Kim, I think the shapes add up to 15 because the number of sides eg hexagon 6 + pentagon 5 + square 4 equals 15 sides, not that each shape equals 5. Have you considered that?Jenihttps://www.blogger.com/profile/07970542077167850294noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-87999561749364140702018-04-17T09:03:39.622+05:302018-04-17T09:03:39.622+05:30If each confuguration in equation 1 was equal to 1...If each confuguration in equation 1 was equal to 15, and each configuration consists of 3 shapes each equalivalent to 5, the answer to this whole puzzle would be 35.Kimhttps://www.blogger.com/profile/14097386563135369230noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-17439326920744699162018-04-06T03:30:57.250+05:302018-04-06T03:30:57.250+05:30If you replace the pictures with variables, then l...If you replace the pictures with variables, then let's assume: x + x + x = 45. So x = 15. Then in the second equation y + y + x = 23. So 2y = 23 - 15. y = 4. The third equation is y + z + z = 10. Then we get 4 + 2z = 10. z = 3. In the last equation we have a + b + b + c = ??. We have no idea what a, b and c are so it can't be answered. Just because 4 bananas = 4 doesn't mean 3 bananas = 3. Just like the variable x isn't half as much as the variable xx (not the same as 2x). You have to assume the pictures are related somehow, but they aren't necessarily related. The last answer could be 0 if the 3 variables all equal 0. So, the puzzle is really not solvable.Seth Dunayerhttps://www.blogger.com/profile/09325899485797011183noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-38045492553663337662017-10-29T09:42:38.159+05:302017-10-29T09:42:38.159+05:30
I thought the answer was 38, but there is a shad... <br />I thought the answer was 38, but there is a shading scheme with the final shape to be taken into account. I believe the answer is 56, but I cannot rule out 53. See my original reasoning with the edited reasoning below.<br /><br />The first line has 3 shape sets which = 45, so each shape set = 15. Each shape set has 3 shapes, a square, a pentagon, and a hexagon. 4 sides, 5 sides, 6 sides. 4+5+6=15.<br /><br />The second line has a shape set and two bunches of bananas which = 23. We know each shape set is 15, leaving 8 between the two bunches of bananas. Each bunch has 4 bananas displayed. 4+4=8, so each banana displayed is 1.<br /><br />The third line has a bunch of 4 bananas, and 2 clocks which = 10. Each banana is 4, so we are left with 6 between the two clocks. Each clock is at three, so each hour displayed is 1. 4 bananas + 3 hours + 3 hours = 10.<br /><br />The fourth line is tricky. First, we have a clock. However, the clock is at 2 instead of three, so we have 2 hours. Second, we have two bunches of bananas. However, because there are 3 bananas displayed instead of four in each bunch, it represents 2 bunches of 3 bananas each. Third, we have a shape set. However, the shape set is absent the square. Since we have the pentagon and hexagon, and we count each side, we have 11 sides.<br /><br />2 hours + 3 bananas + 3 bananas × 11 sides = ???<br /><br />2+3+3×11=??<br /><br />Following the rules of math, we multiply first before adding:<br /><br />3×11=33<br /><br />We then add:<br /><br />2+3+33=38<br /><br />The answer then is 38.<br /><br />*EDIT<br /><br />I missed the shading scheme of the final shape. Looking at the puzzle, the center of the pentagon is the darkest of the shades. Looking at the previous examples of the shape group, the shading gets progressively darker, indicating that all 3 shapes are a transparent shade of the level. As they stack, they get progressively darker. This proves that my original answer of 38 is wrong.<br /><br />I believe that the hexagon is a shade darker in the final line than it was in the previous lines, indicating that there are two hexagons and one pentagon (pentagon being the same shade as the square, meaning there are 3 shapes still in the shape group, not two, and that the sides of the shape must count). If the hexagon is the middle shade, then there are two hexagons and one pentagon, with a final shape group value of 17, and so the answer would be 56. However, it is difficult for me to tell if the shade is the lightest or middle shade, so I cannot rule out that the hexagon is the lightest shade, which would mean there are two pentagons and one hexagon, and so the answer would be 53.<br /><br />So the answer is either:<br /><br />2+3+3×16=2+3+48=53<br /><br />- OR - (and I think the more likely of the two answers)<br /><br />2+3+3+17=2+3+51=56Anonymoushttps://www.blogger.com/profile/08229246956936005824noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-90335383142729368282017-10-13T02:39:42.706+05:302017-10-13T02:39:42.706+05:30This comment has been removed by the author.Squishyhttps://www.blogger.com/profile/02813842209225202793noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-26425492704444541762017-06-08T15:04:12.819+05:302017-06-08T15:04:12.819+05:30Yes Soel,
From third equation we get that, each h...Yes Soel,<br /><br />From third equation we get that, each hour on clock = 1.<br /><br />Final answer is : 38Forward Junctionhttps://www.blogger.com/profile/09656543763051221546noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-89385904601488410982017-06-07T12:04:06.578+05:302017-06-07T12:04:06.578+05:30i don't know how, but is it anyhow possible to...i don't know how, but is it anyhow possible to vary the value of a watch with respect to time?soel hossainhttps://www.blogger.com/profile/03965311553394456229noreply@blogger.com