tag:blogger.com,1999:blog-4087678678967641447.post2658808031459679893..comments2020-06-03T01:16:02.464-04:00Comments on Forward Junction Puzzles: Muscle Freak Mask Dumbbell Puzzle | with AnswerForward Junctionhttp://www.blogger.com/profile/09656543763051221546noreply@blogger.comBlogger7125tag:blogger.com,1999:blog-4087678678967641447.post-50586739385858602922020-05-31T04:25:14.888-04:002020-05-31T04:25:14.888-04:00Ooooops! After going around in circles trying to h...Ooooops! After going around in circles trying to how assign a logical value to the handle mathematically. Visiting forums and comparing responses. I realized the answer is 44. The value of the discs big or small is assigned. It is not created by an interpretation of a relationship to weight. If you want to assigned zero to the handle is perfectly possible and valid. The only real clue is that we have 6 discs and it’s value adds up to 6. So it is mathematically correct to assign a value of 1 per disc. The units of the puzzle are never mentioned, if they were lbs, kg, or other weight unit, we would be in trouble. I’d love to see the puzzle with an extra line with weights and another value to determine if we should after the right unit theory.Math Loverhttps://www.blogger.com/profile/03408513427404650010noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-3450226437269184062020-05-31T03:30:27.798-04:002020-05-31T03:30:27.798-04:00In my opinion. I would say Músico has the closest ...In my opinion. I would say Músico has the closest possible answer, discs are worth (.5),(1),(1.5). However the handle is not being counted. In order to work, the value of it would have to be zero. Something that is not logical either.<br />Although 49 seems what appears to be the right answer. It would be in my opinion an assumption. If the discs were in piles without the handle, I’d say it was irrevocably 49. BTW, the rule of simplification says to perform multiplication before addition if no parenthesis is found.<br />Math Loverhttps://www.blogger.com/profile/03408513427404650010noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-879668948107687562020-04-29T21:12:57.978-04:002020-04-29T21:12:57.978-04:00What is it?What is it?Shirlene M.https://www.blogger.com/profile/07740184033057693097noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-59548644765056448992020-04-28T02:03:40.068-04:002020-04-28T02:03:40.068-04:00Wrong answer. First learn yhe rule of simplificati...Wrong answer. First learn yhe rule of simplificationmaitreyeehttps://www.blogger.com/profile/08035664808991300798noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-15447150850918705862020-04-18T04:44:01.381-04:002020-04-18T04:44:01.381-04:00Watch this youtube video for the correct answer of...Watch this youtube video for the correct answer of this puzzle.<br />https://youtu.be/EUNeP6cb-G4Puzzle Addahttps://www.blogger.com/profile/15960754481877684369noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-61753934002162247642020-04-17T23:50:13.206-04:002020-04-17T23:50:13.206-04:00attention to dumbbells ... The weights are not the...<br />attention to dumbbells ... The weights are not the same dimensions, so they will not have the same weight! Considering the weight "a" the lightest, "b" the intermediate and "c" the heaviest, we arrive at the following condition 2a <2b <2c where its sum will be 6. Therefore 2a = 1, 2b = 2, 2c = 3<br />1 + 2 + 3 = 6<br />In the dumbbells of the last row, the pairs "a" are not found, each one is worth (2b + 2c) 5<br />That said, the result will be:<br />5 + 5 + (5 + 5 + 3) x3 = 49<br />hugMusicohttps://www.blogger.com/profile/07601819417142000673noreply@blogger.comtag:blogger.com,1999:blog-4087678678967641447.post-44453019686017933602020-04-16T09:28:02.822-04:002020-04-16T09:28:02.822-04:00that seems illogical.. Just look at the sizes of r...that seems illogical.. Just look at the sizes of rings, hence the values couldn't be same.ധൃഷ്ടദ്യുമ്നന്https://www.blogger.com/profile/11669069166271633872noreply@blogger.com